Question #107293
Determine the dimensions of q when q=1/2pv^2 when p =density and v=velocity
1
Expert's answer
2020-04-01T10:12:48-0400
q=12ρv2.q=\frac{1}{2}\rho v^2.[q]=[ρ]×[v]2[q]=[\rho]\times [v]^2=kg/m3×(m/s)2=kg/(ms2)=N/m2=Pa.=\rm kg/m^3\times (m/s)^2=kg/(m\cdot s^2)=N/m^2=Pa.

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