Question

A water sprinkler bursts from the ground with a velocity of 8.46m/s at an angle of 45°. Find:


I) The magnitude height


II) The range of the sprinkler


III) Total time the water took to reach ground

Answer 1

i)

$$h=\frac{v^2\sin^2{45}}{2g}=\frac{8.46^2\sin^2{45}}{2\cdot9.8}=1.83\ m$$

ii)

$$R=\frac{v^2\sin{(2\cdot45)}}{g}=\frac{8.46^2}{9.8}=7.30\ m$$

iii)

$$t=2\frac{v\sin{45}}{g}=2\frac{8.46\sin{45}}{9.8}=1.22\ s$$