Question #106941
A long hollow cylinder conductor (inner radius = 2.0 mm, outer radius = 4.0 mm) carries a current of 12 A distributed uniformly across it's cross section.A long wire which is coaxial with the cylinder carries an equal current in the same direction . Determine the magnitude of the field 3.0 mm from the axis.
1
Expert's answer
2020-03-30T08:05:04-0400

We can use Ampere's law to find the magnetic field


Bdl=μ0ien\int Bdl=\mu_0 i_{en}

2πrB=μ0(i1+i2π(3222)π(4222))2\pi rB=\mu_0\left(i_1+i_2\frac{\pi(3^2-2^2)}{\pi(4^2-2^2)}\right)

2π(0.003)B=4π107(12+5)2\pi (0.003)B=4\pi\cdot10^{-7}\left(12+5\right)

B=1.1103T=1.1 mTB=1.1\cdot 10^{-3}T=1.1\ mT


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