Question #106243
In a series circuit there are 3 separate resistors of 3, 8 and 5 ohms. What is the total resistance in the circuit?
1
Expert's answer
2020-03-24T09:56:51-0400

If they are connected in parallel:


R=3+8+5=16 ΩR=3+8+5=16\ \Omega

If they are connected in series:


1R=13+18+15\frac{1}{R'}=\frac{1}{3}+\frac{1}{8}+\frac{1}{5}

R=1.519 ΩR'=1.519\ \Omega


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