Question

An object is placed at a distance of 30 cm in t of a convex mirror of focal
length 15 cm find position and nature of image

Answer 1

$$\frac{1}{30}+\frac{1}{q}=-\frac{1}{15}$$

$$q=-10\ m$$

$$m=(-1)\frac{-10}{30}=\frac{1}{3}>0$$

Image is virtual and  behind the mirror.