Question

Radius =2.7 cm , Q=6.3 × 10^-8 and volume charge density = ?

Answer 1

$$\rho_C=\frac{Q}{V}$$

$$\rho_C=\frac{3Q}{4\pi R^3}$$

$$\rho_C=\frac{3(6.3\cdot 10^{-8})}{4\pi (0.027)^3}=7,6\cdot 10^{-4}\frac{C}{m^3}$$