a)
V=k0.5dQ1+k0.5dQ1=2kdQ1+Q2
V=2(8.99⋅109)0.355⋅10−9−3⋅10−9=103 V
b)
Ep=kdQ1Q2
Ep=(8.99⋅109)0.35(5⋅10−9)(−3⋅10−9)=−3.85⋅10−7 J Negative sign means that positive work must be done to separate the charges (bring them up to a state of zero potential energy).
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