a)
"V=2(8.99\\cdot10^{9})\\frac{5\\cdot10^{-9}-3\\cdot10^{-9}}{0.35}=103\\ V"
b)
"E_p=(8.99\\cdot10^{9})\\frac{(5\\cdot10^{-9})(-3\\cdot10^{-9})}{0.35}=-3.85\\cdot10^{-7}\\ J"
Negative sign means that positive work must be done to separate the charges (bring them up to a state of zero potential energy).
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