Question #105926
An object of mass m = 50 g is released from rest from a height h = 150 m above the ground. Calculate the kinetic energy and the potential energy of the object at the height H = h/5.
1
Expert's answer
2020-03-19T11:30:48-0400

The total energy of an object at the initial point


E=KE+PE=0+mghE=KE+PE=0+mgh=0.05×9.8×150=73.5J=0.05\times 9.8\times 150=73.5\:\rm J

At the height H=h/5=30m,H=h/5=30\:\rm m, the potential energy of an object


PE=mgH=0.05×9.8×30=14.7JPE=mgH=0.05\times 9.8\times 30=14.7\:\rm J

The kinetic energy


KE=EPE=73.514.7=58.8JKE=E-PE=73.5-14.7=58.8\:\rm J

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