Answer to Question #105837 in Physics for Rfa

Question

A meter stick in static equilibrium is supported by a support cable. A 120gram mass is attached to the 90cm mark on the stick. The new location of the support cable is then at the 80cm mark on the meter stick.
What’s the mass of the meter stick? And determine the tension of the support cable.

Answer 1

1)

$$m(50-20)=(120)(10)$$

$$m=40\ g$$

2)

$$T=(40+120)9.8=1568\ N$$