Answer to Question #105788 in Physics for olabisi

Question #105788
The velocity of a solar powered car as a function of time. The driver accelerates from a stop sign. Cruises for 20s at a constant speed of 60km/hr and then brakes to come to a stop 40s after leaving the stop sign
a) Compare the average acceleration during the following time intervals
i) t=0 to t=10s;
ii) t= 30s to t=40s
iii) t=10 to t= 30s
iv) t=0 to t=40s
b) what is the instantaneous acceleration at t = 20s and t=35s ?
1
Expert's answer
2020-03-18T10:15:19-0400


a) i)


a=603.610=1.67ms2a=\frac{60}{3.6\cdot 10}=1.67\frac{m}{s^2}

ii)


a=0603.610=1.67ms2a=\frac{0-60}{3.6\cdot 10}=-1.67\frac{m}{s^2}

iii)


a=0ms2a=0\frac{m}{s^2}

iv)


a=0040=0ms2a=\frac{0-0}{40}=0\frac{m}{s^2}

b)


a(20)=0ms2a(20)=0\frac{m}{s^2}

a(35)=1.67ms2a(35)=-1.67\frac{m}{s^2}


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Comments

Assignment Expert
01.02.21, 22:36

Dear Raheem, we need need multiplier 1/3.6 to convert speed to m/s

Raheem
01.02.21, 04:39

Where did the 3.6 come from?

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