Answer to Question #105521 in Physics for Lily
2020-03-13T16:22:09-04:00
A sound wave has a frequency of 738 Hz in air
and a wavelength of 0.5 m.
What is the temperature of the air? Assume the velocity of sound at 0◦C is 333 m/s.
Answer in units of ◦C
1
2020-03-16T13:14:57-0400
v ( T ) = f λ = ( 738 ) ( 0.5 ) = 369 m s v(T)=f\lambda=(738)(0.5)=369\frac{m}{s} v ( T ) = f λ = ( 738 ) ( 0.5 ) = 369 s m
T = T 0 ( ( v ( T ) v 0 ) 2 − 1 ) T=T_0\left(\left(\frac{v(T)}{v_0}\right)^2-1\right) T = T 0 ( ( v 0 v ( T ) ) 2 − 1 )
T = 273 ( ( 369 333 ) 2 − 1 ) = 62.2 ° C T=273\left(\left(\frac{369}{333}\right)^2-1\right)=62.2\degree C T = 273 ( ( 333 369 ) 2 − 1 ) = 62.2° C
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