Solution.
m(H2O)=300 g−150 g=150 gm(H2O) = 300 \ g - 150 \ g = 150 \ gm(H2O)=300 g−150 g=150 g
V(H2O)=m(H2O)ρ(H2O)=150 cm3V(H2O) = \frac{m(H2O)}{\rho(H2O)} = 150 \ cm^3V(H2O)=ρ(H2O)m(H2O)=150 cm3
m(X)=310 g−150 g=160 gm(X) = 310 \ g - 150 \ g = 160 \ gm(X)=310 g−150 g=160 g
V(H2O) = V(X)
ρ(X)=m(X)V(X=1.07 gcm3\rho(X) = \frac{m(X)}{V(X} = 1.07 \ \frac{g}{cm^3}ρ(X)=V(Xm(X)=1.07 cm3g
Answer:
ρ(X)=1.07 gcm3\rho(X)= 1.07 \ \frac{g}{cm^3}ρ(X)=1.07 cm3g
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