As per the given question,
Collector area (A)=5cm2
Plasma potential = 25V
energy of plasma (Te)=2 eV
We know that Q= ne
b)
Collector current on probe (i)=2mA
So, i=IAeKTe
i=2×10−3×e273.15×1.372×10−162×1.6×10−19
i=2×10−3×e0.0085×10−3
i=2×10−3×e8.5×10−6 A
a)
From the option b, we can conclude that,
n′=ei=1.6×10−192×10−3×e8.5×10−19
n′=1.25×1016×e8.5×10−19
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