Answer to Question #104642 in Physics for Maddy

Question

Driver A pulls onto a highway and travels at a rate of 28.00 m/s. Driver B pulls onto the highway 9.75 minutes later. She accelerates from an initial speed of 25 m/s to 35 m/s, over 95 mins. Both drivers are exiting the highway at the same exit, which is a distance of 4.75 km from where they entered. Determine which driver will exit first.

Answer 1

$$s=v(t_a+T)$$

$$4750=28(t_a+9.75\cdot 60)$$

$$t_a=-415\ s$$

It means that driver A will exit before driver B pulls onto the highway.

Thus, driver A will exit first.