Consider the following situation:
If the point A is 0.1 m higher than the point B (the lowest point of the trajectory), the speed can be expressed from energy conservation law:
"mgh=\\frac{1}{2}mv^2,\\\\\n\\space\\\\v=\\sqrt{2gh}=\\sqrt{2\\cdot9.8\\cdot0.1}=1.4\\text{ m\/s}."
We don't even need to know the mass!
Since the total mechanical energy is conserved, the bob will reach the same height at point C after passing the bottom B.
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