An arrow is fired by an archer at a speed of 5m/s. Its path has the equation of 220st t=−meters after t seconds.
How high does the arrow go and find the speed covered by the rocket when its 3m above the ground?
1
Expert's answer
2020-03-02T10:21:01-0500
From the conservation of energy:
"mgH=0.5mv^2"
Height of an arrow:
"H=\\frac{v^2}{2g}=\\frac{5^2}{2(9.8)}=1.3\\ m"
The speed covered by the rocket when its 3m above the ground:
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