Question #103854
An object moving on the x axis with a con- stant acceleration increases its x coordinate by 232 m in a time of 2.69 s and has a velocity of 20 m/s at the end of this time.
Determine the acceleration of the object
1
Expert's answer
2020-02-27T10:04:52-0500

The distance traveled by the object


d=vi+vf2t,d=\frac{v_i+v_f}{2}t,

so, the initial velocity


vi=2dtvf=2×2322.6920=152.5m/s.v_i=\frac{2d}{t}-v_f=\frac{2\times 232}{2.69}-20=152.5\:\rm m/s.

The acceleration of the object


a=vfvit=20152.52.69=49.25m/s2.a=\frac{v_f-v_i}{t}=\frac{20-152.5}{2.69}=-49.25\:\rm m/s^2.


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