Answer to Question #103722 in Physics for issac

Question #103722
Calculate the magnitude of Electrostatic force between two human beings
each having mass 100Kg and are 1m apart with 1% excess of electron.
(Molecular mass of H2O= 18gms)
Assume Human Body is made up of 100% water.
1
Expert's answer
2020-02-25T10:24:14-0500
N=mμNA=1000.0186.021023=3.341027N=\frac{m}{\mu }N_A=\frac{100}{0.018 }6.02\cdot 10^{23}=3.34\cdot 10^{27}

Q=0.01Ne=0.01(3.341027)(1.61019)=5.34106CQ=0.01Ne=0.01(3.34\cdot 10^{27})(1.6\cdot 10^{-19})=5.34\cdot 10^{6}C

F=kQ2r2F=k\frac{Q^2}{r^2}

F=9109(5.34106)212=2.61023NF=9\cdot 10^{9}\frac{(5.34\cdot 10^{6})^2}{1^2}=2.6\cdot 10^{23}N


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