Question #103092
Velocity of a particle is expressed as
Vx=40-5t² m/s.
(a) find average acceleration.
(b)find instantaneous acceleration.
(C)Draw the graph of this question.
1
Expert's answer
2020-03-19T11:31:19-0400

(a) The average acceleration


ax=v2v1t2t1=(405t22)(405t12)t2t1a_x=\frac{v_2-v_1}{t_2-t_1}=\frac{(40-5t_2^2)-(40-5t_1^2)}{t_2-t_1}=5(t2+t1).=-5(t_2+t_1).

(b) The instantaneous acceleration


ax(t)=vx(t)=(405t2)=10t.a_x(t)=v_x'(t)=(40-5t^2)'=-10t.

(c)

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