Given:
A=16i+16j;{\bf A}=16{\bf i}+16{\bf j};A=16i+16j;
C=16i−32j.{\bf C}=16{\bf i}-32{\bf j}.C=16i−32j.
The sum of vectors
A+C=16i+16j+16i−32j=32i−16j.{\bf A}+{\bf C}=16{\bf i}+16{\bf j}+16{\bf i}-32{\bf j}=32{\bf i}-16{\bf j}.A+C=16i+16j+16i−32j=32i−16j.
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