When the sphere is moulded into a uniform cylindrical wire volume of the material remains constant
Volume of the sphere =43πr′3\dfrac{4}{3}\pi r'^334πr′3
Volume of cylinder = πr2h\pi r^2hπr2h
→πr2h=43π(r′)3\to \pi r^2h= \dfrac{4}{3}\pi (r')^3→πr2h=34π(r′)3
→r2h=(4/3)∗1000\to r^2h=(4/3)*1000→r2h=(4/3)∗1000
→h=(4/3)∗1000r2\to h= (4/3)*\dfrac{1000}{r^2}→h=(4/3)∗r21000 length of the wire
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