Answer to Question #102216 in Physics for Nyx

Question

An object weighing 296 N in air is immersed
in water after being tied to a string connected
to a balance. The scale now reads 265 N .
Immersed in oil, the object appears to weigh
272 N .
Find the density of the object.
Answer in units of kg/m3.
Don't round answer.

Find the density of the oil.
Answer in units of kg/m3.

Answer 1

$W-W_w=\rho_wgV$

$296-265=1000(9.8)V$

$V=0.00316\ m^3$

Thus,

$\rho_{object}=\frac{W}{gV}$

$\rho_{object}=\frac{296}{(0.00316)(9.8)}=9560\frac{kg}{m^3}$

$W-W_o=\rho_ogV$

$296-272=\rho_o(9.8)(0.00316)$

$\rho_{o}=775\frac{kg}{m^3}$