Question

A string of length 1.0 m vibrates in 10 loops. If the total mass of string the is 1.0 x 10^ (-3) kg and the tension in it is 10 n, calculate the frequency of the vibration

Answer 1

The frequency of the string can be computed via the following formula: $f = \frac{1}{2L}\sqrt{\frac{T}{m/L}}$, where $L$ is the length of the string, $T$ is the tension of the string, $m$ is the mass of the string.

Substituting $L = 1 m, m = 10^{-3} kg, T = 10 N$, obtain $f = 50 {Hz}$.