Given:
"a_x=-25.0,\\quad a_y=40.0"The magnitude of the vector "\\bf a"
"a=\\sqrt{a_x^2+a_y^2}=\\sqrt{(-25.0)^2+40.0^2}=47.2"The angle between vector "\\bf a" and positive direction of x-axis
"\\theta=\\tan^{-1}\\frac{a_y}{a_x}=\\pi-\\tan^{-1}\\frac{40.0}{25.0}=122^{\\circ}"
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