The electric field of an infinite line charge is given by
The electric field of point charge placed at distance "d" from the origin is given by
At the point where the electric field is zero
Hence
"\\frac{\\lambda}{2\\pi r \\varepsilon_0}=\\frac{q}{4\\pi \\varepsilon_0 (r-d)^2}"
After some algebra, we obtain an equation
"r^2-(2d+\\frac{q}{2\\lambda})r+d^2=0"
"r^2-6.5r+9=0"
Roots:
For "0<r<d" we obtain "r=2\\:\\rm m."
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