Question #101400
An Atwood machine is constructed using two
wheels (with the masses concentrated at the
rims). The left wheel has a mass of 1.8 kg and
radius 20.01 cm. The right wheel has a mass
of 2.8 kg and radius 28.05 cm. The hanging
mass on the left is 1.55 kg and on the right
1.27 kg. What is the acceleration of the system?
The acceleration of gravity is 9.8 m/s2. Answer in units of m/s2.
Don't round answer
1
Expert's answer
2020-01-20T05:21:09-0500


For each pulley:


τ=Iα=mra\tau=I\alpha=mra

For left pulley:


T1r1T2r1=m1r1am1a=T1T2T_1r_1-T_2r_1=m_1r_1a\to m_1a=T_1-T_2

For right pulley:


T2r2T3r2=m2r2am2a=T2T3T_2r_2-T_3r_2=m_2r_2a\to m_2a=T_2-T_3

Then,


m3a=m3gT1m_3a=m_3g-T_1

m4a=m4g+T3m_4a=-m_4g+T_3

Adding these four equations:


(m1+m2+m3+m4)a=(m3m4)g(m_1+m_2+m_3+m_4)a=(m_3-m_4)g

(1.8+2.8+1.55+1.27)a=(1.551.27)9.8(1.8+2.8+1.55+1.27)a=(1.55-1.27)9.8

a=0.370ms2a=0.370\frac{m}{s^2}


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