For each pulley:
τ=Iα=mraFor left pulley:
T1r1−T2r1=m1r1a→m1a=T1−T2 For right pulley:
T2r2−T3r2=m2r2a→m2a=T2−T3Then,
m3a=m3g−T1
m4a=−m4g+T3 Adding these four equations:
(m1+m2+m3+m4)a=(m3−m4)g
(1.8+2.8+1.55+1.27)a=(1.55−1.27)9.8
a=0.370s2m
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