Question #101132
A frog with the mass 30 g rests on the little wooden square float with square 100 cm2 and height 5 cm. How high shall the frog jump in order to make a float sink into the water completely. The water density is 1000 kg/m3, The wood density is 740 kg/m3. Please present the result in meters, rounded up to 3 significant digits.
1
Expert's answer
2020-01-09T10:37:42-0500

From the conservation of energy:


mgH=WmgH=W

Fnet=(ρwρ)gAyF_{net} =(\rho_w-\rho)gAy

W(y)=0.5(ρwρ)gAy2W(y)=0.5(\rho_w-\rho)gAy^2

W=W(h)=0.5(ρwρ)gAh2W=W(h)=0.5(\rho_w-\rho)gAh^2

So,


mgH=0.5(ρwρ)gAh2mH=0.5(ρwρ)Ah2mgH=0.5(\rho_w-\rho)gAh^2\to mH=0.5(\rho_w-\rho)Ah^2

(0.03)H=0.5(1000740)(0.01)(0.05)2(0.03)H=0.5(1000-740)(0.01)(0.05)^2

H=0.108 mH=0.108\ m


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Comments

Tosin
13.01.20, 19:30

I seem not to understand this, or maye the formula used is different

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