Answer to Question #100861 in Physics for natnael
A projectile is fired in such a way that its horizontal range is equal to three times its maximum height. What is the angle of projection?
1
2020-01-03T09:21:01-0500
"R=3H"
"\\frac{v^2\\sin{2\\theta}}{g}=2\\frac{v^2\\sin{\\theta}\\cos{\\theta}}{g}=3\n\\frac{v^2\\sin^2{\\theta}}{2g}"
"\\tan \\theta=\\frac{4}{3}"
"\\theta=53\\degree"
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