2019-12-22T07:11:49-05:00
Four charged particles with charges of
Q1=80nc
Q2=-60nc
Q3=40nc
Q4=-30nc. What is flux for a Gaussian cube of each side down if it encloses
A,q1 and q2
B.q1,q1 and q3
C. All the four charges
1
2019-12-24T14:28:17-0500
A.
Φ = q 1 + q 2 ϵ 0 = 80 ⋅ 1 0 − 9 − 60 ⋅ 1 0 − 9 8.85 ⋅ 1 0 − 12 = 2.3 ⋅ 1 0 3 N m 2 C \Phi=\frac{q_1+q_2}{\epsilon_0}=\frac{80\cdot 10^{-9}-60\cdot 10^{-9}}{8.85\cdot 10^{-12}}=2.3\cdot 10^{3}\frac{Nm^2}{C} Φ = ϵ 0 q 1 + q 2 = 8.85 ⋅ 1 0 − 12 80 ⋅ 1 0 − 9 − 60 ⋅ 1 0 − 9 = 2.3 ⋅ 1 0 3 C N m 2 B.
Φ = q 1 + q 2 + q 3 ϵ 0 = 80 ⋅ 1 0 − 9 − 60 ⋅ 1 0 − 9 + 40 ⋅ 1 0 − 9 8.85 ⋅ 1 0 − 12 = 6.8 ⋅ 1 0 3 N m 2 C \Phi=\frac{q_1+q_2+q_3}{\epsilon_0}=\frac{80\cdot 10^{-9}-60\cdot 10^{-9}+40\cdot 10^{-9}}{8.85\cdot 10^{-12}}=6.8\cdot 10^{3}\frac{Nm^2}{C} Φ = ϵ 0 q 1 + q 2 + q 3 = 8.85 ⋅ 1 0 − 12 80 ⋅ 1 0 − 9 − 60 ⋅ 1 0 − 9 + 40 ⋅ 1 0 − 9 = 6.8 ⋅ 1 0 3 C N m 2 C.
Φ = q 1 + q 2 + q 3 + q 4 ϵ 0 = ( 80 − 60 + 40 − 30 ) ⋅ 1 0 − 9 8.85 ⋅ 1 0 − 12 = 3.4 ⋅ 1 0 3 N m 2 C \Phi=\frac{q_1+q_2+q_3+q_4}{\epsilon_0}=\frac{(80-60+40-30)\cdot 10^{-9}}{8.85\cdot 10^{-12}}=3.4\cdot 10^{3}\frac{Nm^2}{C} Φ = ϵ 0 q 1 + q 2 + q 3 + q 4 = 8.85 ⋅ 1 0 − 12 ( 80 − 60 + 40 − 30 ) ⋅ 1 0 − 9 = 3.4 ⋅ 1 0 3 C N m 2
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