(a)
the thermal efficiency
k=(h4–h1)(h1–h2)−(h4–h3)(1)
Using (1) we got
k=(2758–183.3)(2758–1939.5)−(183.3–173.9)=0.314
(b)
the mass flow rate of the steam is
m=809.1kJ/kg)(100MV)(1000kV/MV)=4.449×105kg/h
(с)
the rate of heat transfer to the steam
Q=m(h1−h4)=3.182×105kW
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