Answer to Question #100621 in Physics for Abraham

Question

Two helicopters A,B fly in a space with velocities Va=i+2j+3k and Vb=4i+2j-4k. Relative to a stationary observer at origin 0,0,0 if the helicopters fly at right angle with each other, there distance apart after 5second is

Answer 1

The velocity of helicopter B relative helicopter A is

$$\bold{v=(4i+2j-4k)-(i+2j+3k)=(3i-7k)}\frac{m}{s}$$

$$v=\sqrt{3^2+(-7)^2}=7.6\frac{m}{s}$$

$$d=vt=(7.6)(5)=38\ m$$