Answer to Question #100609 in Physics for CC

Question #100609
You serve the tennis ball to your opponent from a hight is 2.6m with an initial velocity of 20.4m/s. What is the time it takes to reach your opponent? What is the total distance it travels? What is the final vertical velocity? What is the final velocity?
1
Expert's answer
2019-12-19T11:36:40-0500

Time:


t=2hg=2(2.6)9.8=0.728 st=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(2.6)}{9.8}}=0.728\ s

The total distance:


d=vxt=(20.4)(0.728)=15 md=v_xt=(20.4)(0.728)=15\ m

The final vertical velocity:


vy=2gh=2(9.8)(2.6)=7.1msv_y=\sqrt{2gh}=\sqrt{2(9.8)(2.6)}=7.1\frac{m}{s}

The final velocity:


v=7.12+20.42=21.6msv=\sqrt{7.1^2+20.4^2}=21.6\frac{m}{s}


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