Time:
"t=\\sqrt{\\frac{2h}{g}}=\\sqrt{\\frac{2(2.6)}{9.8}}=0.728\\ s" The total distance:
"d=v_xt=(20.4)(0.728)=15\\ m" The final vertical velocity:
"v_y=\\sqrt{2gh}=\\sqrt{2(9.8)(2.6)}=7.1\\frac{m}{s}" The final velocity:
"v=\\sqrt{7.1^2+20.4^2}=21.6\\frac{m}{s}"
Comments
Leave a comment