The Newton's second law states
"ma=F_{\\rm net}"In this case
"ma=F_{\\rm fric}=\\mu N=\\mu mg"The total acceleration
"a=\\sqrt{a_n^2+a_{\\tau}^2}=\\sqrt{\\left(\\frac{v^2}{R}\\right)^2+a_{\\tau}^2}"Hence
"a=\\mu g"Finally, the coefficient of static friction
"\\mu=\\frac{\\sqrt{\\left(\\frac{v^2}{R}\\right)^2+a_{\\tau}^2}}{g}"
"=\\frac{\\sqrt{\\left(\\frac{31.5^2}{368}\\right)^2+3.3^2}}{9.8}=0.435"
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