The initial amount of grass: i.
A cow eats a certain amount of grass in one day, call it c.
The field grows by a certain amount each day, call it g.
i+90g−48(90c)=0→i+90g−4320c=0
i+30g−30(120c)=0→1.2i+36g−4320c=0
0.2i−54g=0→i=270g Thus,
270g+30g−30(120c)=0
g=12c It takes 12 cows to eat one day's growth in one day.
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