Question #100100
A boy whirls a storm in a horizontal circle of radius 1.5 and a Height 2 meter above level ground. The string breaks, and the stone flies off horizontally and Strikes the ground after traveling horizontally a distance of 10 meter. What is the magnitude of the centripetal acceleration of the stone during the circular motion?
1
Expert's answer
2019-12-09T09:03:52-0500

Time of flight:


t=2hg=2(2)9.8=0.639 st=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(2)}{9.8}}=0.639\ s

v=dt=100.639=15.6msv=\frac{d}{t}=\frac{10}{0.639}=15.6\frac{m}{s}

The magnitude of the centripetal acceleration of the stone during the circular motion:


a=v2r=15.621.5=160ms2a=\frac{v^2}{r}=\frac{15.6^2}{1.5}=160\frac{m}{s^2}


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