Question #100054
Find the angular momentum if postion vector is perpendicular with 30Ns Momentum of |τ|=0.5m
1
Expert's answer
2019-12-09T08:54:38-0500

The angular momentum is L=r×p\bold L = \bold r \times \bold p, and its absolute value is L=rpsinθL = |\bold r| |\bold p| \sin \theta , where θ\theta is the angle between r\bold r and p\bold p. Given that θ=90\theta = 90^{\circ}, L=0.5m30Ns1=15NmsL = 0.5 m \cdot 30 N s \cdot 1 = 15 N \cdot m \cdot s.


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