let d1d_1d1 be a distance from object to lens, and d2d_2d2 be a distance from image to lens.
then
{Γ=h2h1=d2d1=51F=1d1+1d2=5⇒{d2=5d165=5d1⇒{d2=1.2md1=0.24m\begin{cases} \Gamma = \frac{h_2}{h_1} = \frac{d_2}{d_1} = 5\\ \frac{1}{F}=\frac{1}{d_1}+\frac{1}{d_2} = 5 \end{cases} \Rightarrow \begin{cases} d_2=5d_1\\ \frac{6}{5}=5d_1 \end{cases} \Rightarrow \begin{cases} d_2=1.2 m\\ d_1 = 0.24m \end{cases}{Γ=h1h2=d1d2=5F1=d11+d21=5⇒{d2=5d156=5d1⇒{d2=1.2md1=0.24m
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