Question #95953
A convex lens of power +5D was used to produce a virtual magnified image 5 times the size of the object. Determine the object and image position
1
Expert's answer
2019-10-07T10:50:05-0400

let d1d_1 be a distance from object to lens, and d2d_2 be a distance from image to lens.

then

{Γ=h2h1=d2d1=51F=1d1+1d2=5{d2=5d165=5d1{d2=1.2md1=0.24m\begin{cases} \Gamma = \frac{h_2}{h_1} = \frac{d_2}{d_1} = 5\\ \frac{1}{F}=\frac{1}{d_1}+\frac{1}{d_2} = 5 \end{cases} \Rightarrow \begin{cases} d_2=5d_1\\ \frac{6}{5}=5d_1 \end{cases} \Rightarrow \begin{cases} d_2=1.2 m\\ d_1 = 0.24m \end{cases}


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