So, for a convex mirror
1u+1v=1f\frac{1}{u}+\frac{1}{v}=\frac{1}{f}u1+v1=f1
where
u=−6cmu=-6 cmu=−6cm and f=12cmf=12cmf=12cm
We have
1−6+1v=13→v=0.5cm\frac{1}{-6}+\frac{1}{v}=\frac{1}{3}\to v=0.5cm−61+v1=31→v=0.5cm
The nature of the image is virtual, upright, reduced (smaller).
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