Question

Calculate the critical angle of a material having a refractive index of 1.52 when light passes from the material to air

Answer 1

Relationship between refractive index and critical angle of a material:

$\mu=\frac{1}{sin \space {\theta}_c}$

where $\theta_c$ represent critical angle.

This equation reduces to:

$\theta_c=sin^{-1}\frac{1}{\mu}$

$\theta_c=sin^{-1} \frac{1}{1.52}$

$\theta_c=41.139\degree$