Question #93145

A small object is enclosed in a transparent solid sphere of radius 8 cm. The object is situated at 2 cm from the centre of the sphere. If its image appears to be at 3.2 cm from the nearest side then the refractive index of the material of the sphere is

Expert's answer

Equation of refractive surface is given by formula

n1d+n2f=(n2n1)R(1)\frac{n_1}{d} + \frac{n_2}{f} = \frac{(n_2- n_1)}{R} (1)

In our case, we can rewriter (1) as

n12+13.2=(1n1)10(2)\frac{n_1}{2} + \frac{1}{3.2} = \frac{(1- n_1)}{-10} (2)


Using (2) we get

n1=1.5


Answer

1.5


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