You set up a single slit diffraction experiment in air that produces a diffraction pattern on a screen where the central maximum has a width of 5.3 mm.
You immerse the whole experiment in a fluid of refractive index n = 1.38.
What is the width of the central maximum now that you have immersed the experiment in the fluid? (to 2 s.f and in mm)
1
Expert's answer
2019-05-20T13:51:06-0400
The width of the any maximum is given by formula
"\u0394x = \\frac {\u03bbL}{nd} (1)"
where λ is the wavelength, L is the distance from diffraction grating to screen, n is the refractive index
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