Question

You set up a single slit diffraction experiment in air that produces a diffraction pattern on a screen where the central maximum has a width of 5.3 mm.
You immerse the whole experiment in a fluid of refractive index n = 1.38.
What is the width of the central maximum now that you have immersed the experiment in the fluid? (to 2 s.f and in mm)

Answer 1

The width of the any maximum is given by formula

$$Δx = \frac {λL}{nd} (1)$$

where λ is the wavelength, L is the distance from diffraction grating to screen, n is the refractive index

Using  (1) we get:

3.84

Answer:

3.84