excitation line ν0=18315 cm−1\nu_0 =18315\, cm^{-1}ν0=18315cm−1 , Stokes line νS=ν0−Δν=18116 cm−1\nu_S = \nu_0 - \Delta \nu = 18116 \, cm^{-1}νS=ν0−Δν=18116cm−1
Antistokes line νS=ν0+Δν=2ν0−νS=18514 cm−1⇒λ=540.13 nm\nu_S = \nu_0 + \Delta \nu = 2\nu_0 - \nu_S = 18514 \, cm^{-1} \Rightarrow \lambda = 540.13\, nmνS=ν0+Δν=2ν0−νS=18514cm−1⇒λ=540.13nm
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments