Answer to Question #87563 in Optics for Sridhar

Question

an ordinary light reflected from glass refractive index 1.5 at an angle of incident 45° angle of refraction 28.1° reflection coefficients for perpendicular and parallel Components 0.09337 & 0.00852 respectively calculate degree of polarization
Ans, 83.3%

Answer 1

Degree of polarization:

$$p=\frac {I_{max}- I_{min}} {I_{max}- I_{min}} (1)$$

where I_max=0.09337, I_min=0.00852

Using (1) we got: 83.27%

Answer:

83.3%