in Newton ring experiment the diameter of 5 th dark ring is reduced to half its value on introducing a liquid between lens and glass plate.determine the refractive index of liquid
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Expert's answer
2018-09-19T12:14:08-0400
For the dark ring system: (μd_n^2)/4R=nλ In the first case: μ=1. In the second case: (μ(d_n/2)^2)/4R=nλ Thus, (d_n^2)/4R=(μ(d_n/2)^2)/4R=μ/4 ((d_n^2)/4R) μ/4=1 The refractive index of the liquid is μ=4.
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