Question #72093

A diverging lens, with a focal length of -7 cm is placed 46 cm behind the converging lens. Relative to the diverging lens, where is the image (of the candle) formed by the converging lens?

Expert's answer

Answer on Question #72093-Physics-Optics

A diverging lens, with a focal length of -7 cm is placed 46 cm behind the converging lens. Relative to the diverging lens, where is the image (of the candle) formed by the converging lens?

Solution

The lens formula:


1f=1u+1v\frac{1}{f} = \frac{1}{u} + \frac{1}{v}17=146+1v\frac{1}{-7} = \frac{1}{46} + \frac{1}{v}1v=17146=53322.\frac{1}{v} = \frac{1}{-7} - \frac{1}{46} = -\frac{53}{322}.v=32253=6.075 cm.v = -\frac{322}{53} = -6.075 \text{ cm}.


Answer: -6.075 cm.

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