Question

Calculate the refractive index of the material of an equilateral prism forest the angle of minimum deviation is 60 degree

Answer 1

Answer on Question #68045, Physics / Optics

Calculate the refractive index of the material of an equilateral prism forest the angle of minimum deviation is 60 degree

Solution:

The refractive index of the material: $n = \frac{\sin\left(\frac{A + D}{2}\right)}{\sin\frac{A}{2}}$ (1), where A is the apex angle for a prism, D is the minimum angle of deviation

For equilateral prism: $A = 60{}^\circ$, in task: $D = 60{}^\circ$

Of (1) $\Rightarrow n = \frac{\sin\left(\frac{60{}^\circ + 60{}^\circ}{2}\right)}{\sin\frac{60{}^\circ}{2}} = 1.732$

Answer:

1.732

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