Question #61979

13 In practical experiment inloving the use of optical pins, parallax is reduced or removed if on slightly displacing one's eye from side to side
the object and image are not coincident but move together in same directions
the object and image move in opposite directions relative to each other
the object and image are coincident and move together in the same direction
the object and image are coincident and remain stationary
14 In an experiment with a concave mirror, the image of an optical pin which is 4 times its size was cast on on a screen 6m from the object pin. How far from the object pin should the mirror be placed?
8m
6m
3m
2m
15 The image of an object which is between the concave mirror's reflecting surface and its principal focus is
in front of the mirror erect real and diminished
behind the mirror inverted real and diminished
in front of the mirror erect virtual and enlarged
behind the mirror erect virtual and enlarged

Expert's answer

Answer on Question #61979-Physics-Optics

13 In practical experiment involving the use of optical pins, parallax is reduced or removed if on slightly displacing one's eye from side to side.

the object and image are not coincident but move together in same directions

the object and image move in opposite directions relative to each other

the object and image are coincident and move together in the same direction

the object and image are coincident and remain stationary

Answer

The object and image are not coincident but move together in same directions.

14 In an experiment with a concave mirror, the image of an optical pin which is 4 times its size was cast on a screen 6m from the object pin. How far from the object pin should the mirror be placed?

8m

6m

3m

2m

Solution


The magnification of a mirror is defined as the height of the image divided by the height of the object:


m=hiho=io,m = \frac {h _ {i}}{h _ {o}} = \frac {i}{o},


where oi=6mo - i = 6m

Thus,


14=o6mo\frac {1}{4} = \frac {o - 6 m}{o}


The object position is


o=24m3=8m.o = \frac {2 4 \mathrm {m}}{3} = 8 \mathrm {m}.


Answer: 8m.

15 The image of an object which is between the concave mirror's reflecting surface and its principal focus is in front of the mirror erect real and diminished behind the mirror inverted real and diminished in front of the mirror erect virtual and enlarged behind the mirror erect virtual and enlarged

Answer

When the Object is between the Pole and the Focus:

Consider a ray of light which is parallel to the incident ray and another ray which is passing through the center of curvature. The ray which is passing through the center of curvature retraces its path and the other ray which is parallel to the principal axis after reflection passes through the focus. These rays appear to meet behind the mirror when the reflected rays are extended backwards. The image is virtual, erect and magnified.



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