Question

if sin i is 3/5 what is tan i......

Answer 1

Answer on Question #60260-Physics-Optics

If $\sin i$ is $3/5$ what is $\tan i$

Solution

$$\tan i = \frac{\sin i}{\cos i} = \frac{\sin i}{\sqrt{1 - (\sin i)^2}} = \frac{\frac{3}{5}}{\sqrt{1 - \left(\frac{3}{5}\right)^2}} = \frac{\frac{3}{5}}{\sqrt{16}} = \frac{\frac{3}{5}}{\frac{4}{5}} = \frac{3}{4}$$

Answer: $\frac{3}{4}$

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