Question

how do i determine the energy of a photon with a save length of 3.5 x 10^-8 (negative 8) m? When C= 3.00 x 10^8 m/s H= 6.63 x 10^-34 J-s

Answer 1

Answer on the question #60145, Physics / Optics

Question:

how do i determine the energy of a photon with a save length of $3.5 \times 10^{-8}$ (negative 8) m?

When $C = 3.00 \times 10^{8} \, \text{m/s}$, $H = 6.63 \times 10^{-34} \, \text{J/s}$

Solution:

The relation between energy and wavelength is the following:

$$E = h \frac{c}{\lambda},$$

where $h$ is the Planck's constant, $c$ is the velocity of light and $\lambda$ is the wavelength.

$$E = 6.63 \cdot 10^{-34} \, (J \cdot s) \cdot \frac{3 \cdot 10^{8} \, (m \cdot s^{-1})}{3.5 \cdot 10^{-8} \, (m)} = 5.69 \cdot 10^{-18} \, J$$

Answer: $5.69 \cdot 10^{-18} \, \text{J}$

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