Question #52351

a thin glass lens (refractive index 1.5) has optical power of -5D in air.its optical power in a liquid medium with refractive index 1.6 will be...
1)-25D. 2)25D. 3)-1D. 4) 0.625 D

Expert's answer

Answer on Question #52351-Physics-Optics

A thin glass lens (refractive index 1.5) has optical power of -5D in air. Its optical power in a liquid medium with refractive index 1.6 will be...

1)-25D. 2)25D. 3)-1D. 4) 0.625 D

Solution


P=(μ2μ11)(1R11R2).P = \left(\frac {\mu_ {2}}{\mu_ {1}} - 1\right) \left(\frac {1}{R _ {1}} - \frac {1}{R _ {2}}\right).5=(1.511)(1R11R2).- 5 = \left(\frac {1 . 5}{1} - 1\right) \left(\frac {1}{R _ {1}} - \frac {1}{R _ {2}}\right).50.5=(1R11R2)(1R11R2)=10.- \frac {5}{0 . 5} = \left(\frac {1}{R _ {1}} - \frac {1}{R _ {2}}\right)\rightarrow \left(\frac {1}{R _ {1}} - \frac {1}{R _ {2}}\right) = - 1 0.


Again,


P=(1.51.61)(10)=58D=0.625D.P = \left(\frac {1 . 5}{1 . 6} - 1\right) (- 1 0) = \frac {5}{8} D = 0. 6 2 5 D.


Answer: 4) 0.625 D.

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