Answer on Question #52351-Physics-Optics
A thin glass lens (refractive index 1.5) has optical power of -5D in air. Its optical power in a liquid medium with refractive index 1.6 will be...
1)-25D. 2)25D. 3)-1D. 4) 0.625 D
Solution
P=(μ1μ2−1)(R11−R21).−5=(11.5−1)(R11−R21).−0.55=(R11−R21)→(R11−R21)=−10.
Again,
P=(1.61.5−1)(−10)=85D=0.625D.
Answer: 4) 0.625 D.
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